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听力原文: Visitors to Britain are always complaining about English food. But they do not really know what they are talking about because they rarely get a chance to eat it. Most of the restaurants in large towns have foreign owners and serve foreign food. When visitors are invited to eat in an English home, their hosts often feel they must offer them something foreign and exotic. Those of us who do know English food are a-ware that at its best it can be really very good. On the other hand it is true to say that sometimes it is terrible. Part of the problem is that we are not really interested in food-we eat to live, we do not live 1o eat. So we don't generally spend the necessary time and effort needed to cook really good meals. We prefer food that is simple and easy to cook, or ready prepared food which only needs heating up before eating. You can find the best English food in the country away from the large towns, where life is slower and people are not in such a hurry. But, of course, most visitors come to London. They come because they are interested in shopping and sightseeing. They do not come because of food, so why should they complain about it? Why are visitors to Britain always complaining about English food?
A.
Because they don't eat in an English home.
B.
Because the restaurants they go to serve foreign food.
C.
Because they don't know what they eat is not real English food.
D.
Because people in large towns are too busy to provide them with English food.
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【单选题】如图所示,该量具是 D
A.
游标卡尺
B.
高度游标卡尺
C.
万能游标卡尺
D.
深度游标卡尺
【单选题】如图所示,该量具是
A.
游标卡尺
B.
高度游标卡尺
C.
万能游标卡尺
D.
深度游标卡尺
【判断题】对二元溶液,当T、P一定时,公式【图片】成立
A.
正确
B.
错误
【单选题】如图所示,请问该图形是使用哪种矢量工具绘制的()。
A.
“椭圆”工具
B.
“多边形”工具
C.
“智能多边形”工具
D.
“星形”工具
【单选题】党中央国务院决定扫黑除恶专项斗争在 ( ) 开展?
A.
全国
B.
部分行业
C.
部分地区
D.
0
【单选题】如图所示,该量具是
A.
基准尺
B.
校准尺
C.
塞块
D.
量块
【单选题】如图所示,是工具软件 DiskGenius 运行的界面,则该硬盘扩展分区的容量为 新建位图图像.bmp
A.
7GB
B.
58.2GB
C.
174.7GB
D.
232.9GB
【单选题】如图所示 该量具是
A.
精密游标卡尺
B.
中等游标卡尺
C.
游标卡尺
D.
带表游标卡尺
【单选题】党中央国务院决定扫黑除恶专项斗争在 ( ) 开展?
A.
部分行业
B.
部分地区
C.
全国
【单选题】二元溶液,T, P一定时,Gibbs—Duhem 方程的正确形式是
A.
X1dlnγ1/dX 1+ X2dlnγ2/dX2 = 0
B.
X1dlnγ1/dX 2+ X2 dlnγ2/dX1 = 0
C.
X1dlnγ1/dX 1+ X2dlnγ2/dX1 = 0
D.
X1dlnγ1/dX 1– X2 dlnγ2/dX1 = 0
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