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【单选题】
Consider that Britain is trying to maintain a fixed exchange rate with respect to the U.S. dollar. However, the present situation in the foreign exchange market is conducive for the British pound to depreciate with respect to the U.S. dollar. Which of the following interventions will stem the pressures for depreciation of the pound?
A.
The government of Britain should sell pounds and buy dollars.
B.
The government of Britain should do nothing as a fixed rate will not change.
C.
The government of Britain should buy pounds and sell dollars.
D.
The government of Britain should increase the country’s money supply.
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【单选题】有一原电池: Pt │ Fe 3+ (1 mol/L) , Fe 2+ (1 mol/L) ‖ Ce 4+ (1 mol/L) , Ce 3+ (1 mol/L) │ Pt 则该电池的电池反应是( )
A.
Ce 3+ + Fe 3+ = Ce 4+ + Fe 2+
B.
Ce 4+ + Fe 2+ = Ce 3+ + Fe 3+
C.
Ce 3+ + Fe 2+ = Ce 4+ + Fe 3+
D.
Ce 4+ + Fe 3+ = Ce 3+ + Fe 2+
【单选题】设 , ,则下列结论中不正确的是。( )
A.
是微分式 的原函数
B.
是微分式 的原函数
C.
=
D.
, 只相差一个常数
【单选题】downward
A.
a.依靠的,依赖的
B.
vi.有分歧;不一致
C.
a.向下的 ad.向下地
D.
a.纤细的;易碎的
【单选题】有一原电池 : - ) Pt│Fe 3+ (1mol·L -1 ) , Fe 2 + (1 mol·L -1 ) ‖ Ce 4 + (1 mol·L -1 ) , Ce 3+ (1 . mol·L -1 ) │Pt ( + ) , 则该电池的电池反应是 ( )
A.
Ce 3 + + Fe 3 + = == Ce 4 + + Fe 2 +
B.
Ce 4 + + Fe 2 + = == Ce 3 + + Fe 3 +
C.
Ce 3 + + Fe 2 + = == Ce 4 + + Fe
D.
Ce 4 + + Fe 3 + == = Ce 3 + + Fe 2 +
【单选题】定义:符号 表示不超过实数x的最大整数,如 , , 等,设函数 ,则下列结论中不正确的是 (  )
A.
B.
C.
【单选题】设 是连续型随机变量X的分布函数,则下列结论中不正确的是( )
A.
F(x)不是不减函数
B.
F(x)是不减函数
C.
F(x)是右连续
D.
【简答题】The devices function together as the coupler which helps to improve the vertical stability of the train .In most cases ,buffer devices are included in couplers to mitigate the train jerk .They are als...
【单选题】What is the main function of the transitional devices in writing?
A.
They serve as the bridges between parts of your paper.
B.
They make your writing simple.
C.
They emphasize your main points.
D.
They help you to express your ideas in an easy way.
【单选题】设F 是连续型随机变量 X的分布函数,则下列结论中不正确的是
A.
不是不减函数
B.
是不减函数
C.
是右连续的
【单选题】有一原电池: Pt│Fe 2+ (1 mol·L -1 ) , Fe 3+ (1 mol·L -1 ) ‖ Ce 4+ (1 mol·L -1 ) , Ce 3+ (1 mol·L -1 )│Pt 则该电池的电池反应是
A.
Ce 3+ + Fe 3+ = Ce 4+ + Fe 2+
B.
Ce 4+ + Fe 2+ = Ce 3+ + Fe 3+
C.
Ce 3+ + Fe 2+ = Ce 4+ + Fe
D.
Ce 4+ + Fe 3+ = Ce 3+ + Fe 2+
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