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【简答题】
如图所示，PA⊥平面ABC，点C在以AB为直径的⊙O上，∠CBA＝30°，PA＝AB＝2，点E为线段PB的中点，点M在弧AB上，且OM∥AC. (1)求证：平面MOE∥平面PAC. (2)求证：平面PAC⊥平面PCB. (3)设二面角M—BP—C的大小为θ，求cos θ的值．
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