皮皮学，免费搜题
登录
搜题
【简答题】
Read the extract from a company newsletter and complete the text with the present continuous form of the verbs in brackets. New IT systems for all staff Major improvements in IT are coming to all offices. IT gives us essential tools to do our jobs, and the IT Improvement Project (0) is delivering (deliver) those tools. The aim of the project is to increase efficiency in all aspects of our business through better in-company IT systems. The project's first big success is the new email application: after a very successful trial at head office, we (1) __________ (extend) our in-house email system across the whole company. The project manager, Fraser King, says, We (2) __________ (look) at things that really make a difference and we (3) __________ (improve) them. My team (4) __________ (hold) meetings in all the divisions, and they (5) __________ (use) face-to-face interviews and online surveys to collect information from users. Our key question is "What (6) __________ (not / work) well for you and why not?" "Fraser is in the middle of a four-week fact-finding trip-he (7) __________ (visit) Sydney, Bangkok and Seattle this month, where he (8) __________ (coordinate)the project with local managers. “I (9) __________ (give) lots of presentations about the project - I want everyone to understand what we (10) __________ (do). So far the response is very positive and people are enthusiastic. Everyone's looking forward to using better, more efficient IT tools.”
手机使用
分享
复制链接
新浪微博
分享QQ
微信扫一扫
反馈参考答案：
举一反三
【单选题】函数f(x,y)=4(x−y)−x2−y2f(x,y)=4(x−y)−x2−y2的极值为
A.
f ( 2 , − 2 ) = 8 " role="presentation" style="display: inline-block; line-height: 0; font-size: 19.52px; overflow-wrap: normal; float: none; direction: ltr; max-width: none; max-height: none; min-width: 0px; min-height: 0px; border: 0px; margin: 0px; padding: 1px 0px; color: rgb(0, 0, 0); font-family: "Microsoft YaHei"; position: relative;" > f ( 2 , − 2 ) = 8 f(2,−2)=8
B.
f ( − 2 , − 2 ) = 0 " role="presentation" style="display: inline-block; line-height: 0; font-size: 19.52px; overflow-wrap: normal; float: none; direction: ltr; max-width: none; max-height: none; min-width: 0px; min-height: 0px; border: 0px; margin: 0px; padding: 1px 0px; color: rgb(0, 0, 0); font-family: "Microsoft YaHei"; position: relative;" > f ( − 2 , − 2 ) = 0 f(−2,−2)=0
C.
f ( 2 , 2 ) = 0 " role="presentation" style="display: inline-block; line-height: 0; font-size: 19.52px; overflow-wrap: normal; float: none; direction: ltr; max-width: none; max-height: none; min-width: 0px; min-height: 0px; border: 0px; margin: 0px; padding: 1px 0px; color: rgb(0, 0, 0); font-family: "Microsoft YaHei"; position: relative;" > f ( 2 , 2 ) = 0 f(2,2)=0
D.
f ( − 2 , 2 ) = 8 " role="presentation" style="display: inline-block; line-height: 0; font-size: 19.52px; overflow-wrap: normal; float: none; direction: ltr; max-width: none; max-height: none; min-width: 0px; min-height: 0px; border: 0px; margin: 0px; padding: 1px 0px; color: rgb(0, 0, 0); font-family: "Microsoft YaHei"; position: relative;" > f ( − 2 , 2 ) = 8 f(−2,2)=8
【简答题】基准分为（）基准和（）基准两大类；工艺基准有（）基准，（）基准和（）基准.
【单选题】(2009年) 设z=f(x2一y2)，则dz等于( )。
A.
2x一2y
B.
2xdx一2ydy
C.
f’(x2一y2)dx
D.
2f’(x2一y2)(xdx—ydy)
【单选题】已知点P 1 （x 1 ，y 1 ）、P 2 （x 2 ，y 2 ）分别在直线l上和在l外，若直线l的方程为f（x，y）=0，则方程f（x，y）-f（x 1 ，y 1 ）-f（x 2 ，y 2 ）=0表示（ ）
A.
与l重合的直线
B.
与l平行，且过P 1 的直线
C.
与l平行，且过P 2 的直线
D.
同时过P 1 、P 2 的直线
【单选题】函数f(x,y)=(6x−x2)(4y−y2)f(x,y)=(6x−x2)(4y−y2)的极值为
A.
f ( 3 , 2 ) = 36 " role="presentation" style="display: inline-block; line-height: 0; font-size: 19.52px; overflow-wrap: normal; float: none; direction: ltr; max-width: none; max-height: none; min-width: 0px; min-height: 0px; border: 0px; margin: 0px; padding: 1px 0px; color: rgb(0, 0, 0); font-family: "Microsoft YaHei"; position: relative;" > f ( 3 , 2 ) = 36 f(3,2)=36
B.
f ( 3 , 0 ) = 0 " role="presentation" style="display: inline-block; line-height: 0; font-size: 19.52px; overflow-wrap: normal; float: none; direction: ltr; max-width: none; max-height: none; min-width: 0px; min-height: 0px; border: 0px; margin: 0px; padding: 1px 0px; color: rgb(0, 0, 0); font-family: "Microsoft YaHei"; position: relative;" > f ( 3 , 0 ) = 0 f(3,0)=0
C.
f ( 0 , 2 ) = 0 " role="presentation" style="display: inline-block; line-height: 0; font-size: 19.52px; overflow-wrap: normal; float: none; direction: ltr; max-width: none; max-height: none; min-width: 0px; min-height: 0px; border: 0px; margin: 0px; padding: 1px 0px; color: rgb(0, 0, 0); font-family: "Microsoft YaHei"; position: relative;" > f ( 0 , 2 ) = 0 f(0,2)=0
D.
f ( 3 , 2 ) = 6 " role="presentation" style="display: inline-block; line-height: 0; font-size: 19.52px; overflow-wrap: normal; float: none; direction: ltr; max-width: none; max-height: none; min-width: 0px; min-height: 0px; border: 0px; margin: 0px; padding: 1px 0px; color: rgb(0, 0, 0); font-family: "Microsoft YaHei"; position: relative;" > f ( 3 , 2 ) = 6 f(3,2)=6
【简答题】已知函数f（x）=（x 2 ﹣a）e x ． （1）若a=3，求f（x）的单调区间和极值； （2）若x 1 ，x 2 为f（x）的两个不同的极值点，且 ， 若 恒成立，求实数b的取值范围．
【简答题】设F(x，y)是一个二维随机向量(X，Y)的分布函数，x12，y12，证明： F(x2，y2) - F(x1，y2) - F(x2，y1)+F(x1，y1)≥0．
【简答题】工艺基准有工序基准、( )、测量基准和装配基准之分。
相关题目：
参考解析：
知识点：
题目纠错 0
发布
