用户数据报协议UDP是面向无连接的不可靠的传输协议。A.正确B.错误...

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【判断题】

用户数据报协议UDP是面向无连接的不可靠的传输协议。

正确

错误

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参考答案：

举一反三

【判断题】According to Porter, the policies of government and of business firms can enhance or detract from the four attributes that determine national competitive advantage.

正确

错误

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【单选题】According to Porter, the processes and systems in an organization pursuing differentiation strategy must ________ to avoid negative margins.

create sufficient value to cover their costs

provide products at lowest costs to customers

develop new technologies

increase procurement

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【单选题】listen to the clip and complete each sentence with a proper word:I can’t talk to him if the football’s on. He just sits down and ______, and doesn’t listen to a word I say.

tunes on

zones out

pays heed

drawns

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【多选题】下列对少林内功的习练功用描述正确的有

增强情绪调控力

提高躯体稳定性

调节内脏系统功

增加上肢的力量

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【单选题】According to Porter, ________is usually the most powerful of the five competitive forces.

Rivalry among competing firms

Potential entry of new competitors

Bargaining power of consumers

Bargaining power of suppliers

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【单选题】listen to the clip and complete each sentence with a proper word:As he walked into the dark alley, he was completely ______ of the thief behind him.

captivated

engrossed

unaware

tempted

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【单选题】若 a 、 b 、 c1 、 c2 、 x 、 y 均为整型变量 , 正确的 switch 语句是( )。

switch (a+b); { case 1: y=a+b; break; case 0: y=a-b; break; }

switch a { case c1: y=a-b; break; case c2: x=a*d; break; default: x=a; }

switch (a*a+b*b) { case 3: case 1: y=a+b; break; case 3: y=b-a; break; }

switch(a-b) { default: y=a*b; break; case 3: x=a+b; break; case 10: case 11: y=a-b; break; }

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【判断题】According to Porter, the way to create superior value is to drive down the cost structure of the business and/or differentiate the product in some way so that consumers value it more.

正确

错误

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【单选题】listen to the clip and complete each sentence with a proper word:Samantha will make a good actor. She’s always trying to be the ______.

diversion

fascination

centre of attention

temptation

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【单选题】若a、b、c1、c2、x、y均为整型变量,正确的switch 语句是()

switch (a+b); { case 1: y=a+b; break; case 0: y=a-b; break; }

switch a { case c1: y=a-b; break; case c2: x=a*d; break; default: x=a+b; }