设函数 f ( x )= ax -ln x -3( a ∈R), g ( x )= x e 1 - x . (Ⅰ)若函数 g ( x ) 的图象在点 (0,0) 处的切线也恰为 f ( x ) 图象的一条切线,求实数 a 的值; (Ⅱ)是否存在实数 a ,对任意的 x ∈(0,e],唯一的 x 0 ∈[e -4 ,e],使得 f ( x 0 )= g ( x ) 成立.若存在,求出 a 的取值范围;若不存在,请说明理由. 注:e是自然对数的底数.
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参考答案:
举一反三
【单选题】As to the international business negotiation for both the machine and the relevant technology, the best negotiation method is ( ).
A.
To establish only one negotiation group and let the group to negotiate both the machine and the relevant technology and conclude two pieces of contract which include the machine and the relevant technology respectively
B.
To establish only one negotiation group and let the group to negotiate both the machine and the relevant technology and conclude a piece of contract which includes both commodities
C.
To establish two negotiation groups and let these two groups to negotiate the machine and the relevant technology respectively, however, in the end they conclude only a piece of contract which includes both commodities
D.
To establish two negotiation groups and let these two groups to negotiate the machine and the relevant technology respectively and conclude two pieces of contract which include both commodities respectively