服务器程序接受客户端上传的文件名称fileName,然后获取文件数据保存import flaskapp=flask.Flask(__name__)@app.route("/upload",methods=["POST"])def uploadFile(): msg="" try: if "fileName" in flask.request.values: fileName = flask.request.values.get("fileName") __________________________________ fobj=open("upload "+fileName,"wb") fobj.write(data) fobj.close() msg="OK" else: msg="没有按要求上传文件" except Exception as err: print(err) msg=str(err) return msgif __name__=="__main__": app.run()