皮皮学，免费搜题
登录
搜题
【简答题】
No.2 – (a) What is the entropy ( η ) of the image below, where numbers (0, 20, 50, 99) denote the gray-level intensities? (b) Show step by step how to construct the Huffman tree to encode the above four intensity values in this image. Show the resulting code for each intensity value. Answer: (c) What is the average number of bits needed for each pixel, using your Huffman code? How does it compare to η ? Answer: Average number of bits = 0.5×1 + 0.25×2 + 2×0.125×3 = 1.75 This happens to be identical to η - it only happens when all probabilities are 2 −k where k is an integer. Otherwise, this number will be larger than η .
手机使用
分享
复制链接
新浪微博
分享QQ
微信扫一扫
反馈参考答案：
举一反三
【简答题】Répondez aux questions négativement. Qu'est-ce que c'est?C'est une valise? C'est Catherine? Qui est-ce?C'est Philippe? Estelle est professeur? C'est pour moi? Est-ce chez Paul ici? Ce sont des Françai...
【简答题】Now that their children have all begun to work, the Browns are living in (相对)comfort.
【简答题】翻译 1. —Let's play ping-pong. —That sounds good. — . — . 2. We have many sports cubs. .
【简答题】翻译: How nice the music sounds!
【简答题】请上传下面对话的朗读音频,并完成学生互评。 Qui est-ce? C'est Philippe. Il est l'ami de Fanny. C'est qui? C'est Fanny. Elle est l'amie de Philippe.
【单选题】Now that their children have all begun to work, the Browns are living in ( ) comfort.
A.
relative
B.
responsible
C.
halfway
D.
entirely
【简答题】Qui est-ce ? (Fanny) Est-ce Anne ? (oui) Est-ce que c'est Pascal ? (oui)
相关题目：
参考解析：
知识点：
题目纠错 0
发布
