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【简答题】
在△ABC中，有下列结论： ①若R为△ABC外接圆的半径，则 S △ABC =2 R 2 sinAsinBsinC ； ②sinA+sinB＞sinC，sinA-sinB＜sinC ③若a 2 ＜b 2 +c 2 ，则△ABC为锐角三角形； ④若（a+c）（a-c）=b（b+c），则A为120°； 其中结论正确的是______．（填上全部正确的结论）
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