皮皮学，免费搜题
登录
搜题
【简答题】
四叠体 corpora quadrigemina
手机使用
分享
复制链接
新浪微博
分享QQ
微信扫一扫
反馈参考答案：
举一反三
【单选题】score=input('请输入分数:') if score >= 90: grade = 'A' ______________ grade = 'B' elif score >= 70: grade = 'C' elif score >= 60: grade = 'D' else: grade = 'E' print ('%d belongs to %s' % (score,grade))
A.
else score > = 80:
B.
elif score <= 80:
C.
elif score < 80:
D.
elif score >= 80:
【单选题】等级为A,score=100;等级为B,score=190;等级为C或D,score=60;其他,score=0. if语句,以下正确的是 ( )。
A.
a) if (grade = 'A' ) score = 100; else if ( grade = 'B' ) score = 90; else if ( grade = 'C' || grade = 'D' ) score = 60; else score = 0;
B.
b) if ( grade == 'A' ) score = 100; if ( grade == 'B' ) score = 90; if ( grade == 'C' || grade == 'D' ) score = 60; else score = 0;
C.
c) if ( grade == 'A' ) score = 100; else if ( grade == 'B' ) score = 90; else if ( grade == 'C' ) score = 60; else if ( grade == 'D' ) score = 60; else score = 0;
D.
d) if ( grade == 'A' ) score=100; else if ( grade == 'B' ) score = 90; else if ( grade == 'C' && grade == 'D' ) score = 60; else score = 0;
【简答题】alc_hol
相关题目：
参考解析：
知识点：
题目纠错 0
发布
