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【多选题】
海关接受申报后,申报内容不得修改,报关单证不得撤销,但确有正当理由并经海关审核批准,可以进行以下修改或撤销:
A.
由于计算机、网络系统等方面的原因导致电子数据申报错误的
B.
海关在办理出口货物的放行手续后,由于配载、装运等原因造成原申报货物部分或全部退关,需要修改或撤销报关单证及其内容的
C.
报关员由于操作或书写失误造成申报差错
D.
海关审价、归类审核或专业认定前需对原申报数据进行修改的
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参考答案:
举一反三
【单选题】以下程序运行时,若从键盘输入 9,则输出结果 是 ( ) 。 #inlude int main() { int a=1 ; scanf(" %d ",&a); if(a++<9) printf(" %d\n ",a); else printf(" %d\n ",a); return 0; }
A.
8
B.
9
C.
10
D.
11
【单选题】以下程序运行时,若从键盘输入9,则输出结果是_______。 main() { int a=1; scanf("%d",&a); if(a++<9) printf("%d\n",a); else printf("%d\n",a); }
A.
10
B.
11
C.
9
D.
8
【单选题】石英可以用来制作石英钟,应用的是石英的
A.
热电效应
B.
压电效应
C.
电磁效应
D.
电传导效应
【单选题】In doing "aggregate planning" for a firm producing paint, the aggregate planners would most likely deal with:
A.
just gallons of paint, without concern for the different colors and sizes
B.
gallons of paint, but be concerned with the different colors to be produced
C.
gallons, quarts, pints, and all the different sizes to be produced
D.
all the different sizes and all the different colors by size
E.
none of the above
【单选题】Aggregate planners seek to match supply and demand:
A.
at minimum overall cost
B.
by staying within company policy
C.
(a) and (b)
D.
keeping inventories at a minimum
E.
all of the above
【单选题】Aggregate planners attempt to balance:
A.
demand and inventories
B.
demand and costs
C.
capacity and inventories
D.
capacity and costs
E.
capacity and demand
【单选题】The main disadvantage(s) of informal techniques used for aggregate planning is(are):
A.
they are expensive to do
B.
they may not result in the best plan
C.
they take a long time to do
D.
they require use of a computer
E.
lack of formal education of the planners
【单选题】Accommodating peak demands and effectively using labor resources during periods of low demand would be the goal of aggregate planners in 
A.
Manufacturing
B.
Military
C.
Archeology
D.
Libraries
E.
Financial Services
【单选题】以下程序运行时,若从键盘输入9,则输出结果是_______。 #inlude main() { int a=1; scanf(" %d ",&a); if(a++<9) printf(" %d\n ",a); else printf(" %d\n ",a);
A.
10
B.
11
C.
9
D.
8
【单选题】以下程序运行时,若从键盘输入9,则输出结果是( )。#includeint main(){int a=1;scanf("%d",&a);if(a++<9) printf("%d\n",a);else printf("%d\n",a);}
A.
10
B.
11
C.
9
D.
8
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