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假设 n+1 位的定点整数 X=XnXn-1Xn-2......X2X1X0; Y=YnYn-1Yn-2......Y2Y1Y0; 其中 Xn , Yn 是符号位;且 |X|<2 n ,|Y|<2 n, |X+Y|<2 n ,则 关于补码加减法公式的理解正确的是( )A.
补码加法公式： [X] 补 +[Y] 补 =[X+Y] 补 （ mod 2 n+1 ），其中n 是数值位的位数
B.
补码减法公式： [X-Y] 补 =[X] 补 +[-Y] 补 =[X] 补 -[Y] 补 （ mod 2 n+1 ），
C.
若是8位定点数含1位符号位，则公式中n =7
D.
若把n取值为0，上述公式也适用于定点纯小数的加减运算 [X] 补 +/-[Y] 补 =[X+/-Y] 补 （ mod 2 ）
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