已知等差数列{a n }的首项a 1 =1,公差d>0,且第二项、第五项、第十四项分别是等比数列{b n }的第二项、第三项、第四项. (I)求数列{a n }与{b n }的通项公式; (Ⅱ)设数列{c n }对任意正整数n均有 c 1 b 1 + c 2 m b 2 + c 3 m 2 b 3 +…+ c n m n-1 b n =(n+1)a n+1 成立,其中m为不等于零的常数,求数列{c n }的前n项和S n .
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【单选题】Louise decided to lend money to the author because ______.
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