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【简答题】
可以获取系统当前日期的函数是__。
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参考答案:
举一反三
【单选题】What can be inferred from the fourth paragraph?
A.
Farm areas accept waste from the city in modern society.
B.
There is cheap land to bury waste in modem society.
C.
It is difficult to find space to bury waste in modem society.
D.
Ways to deal with waste in modem society is similar to that of the past.
【单选题】Her beauty ________ him and he swore to stay with her forever.
A.
admired
B.
cheated
C.
swayed
D.
captured
【单选题】已知 25 °C 时 , 某二元弱酸 H 2 A 的 K a1 θ = 1.0×10-7 , K a2 θ = 1.0×10 -14 , 则 0.10mol ・ kg -1 H 2 A 溶液中 A 2– 的浓度约为 1.0×10 -14 mol·Kg -1 ; 在 0.10 mol·Kg -1 H 2 A 和 0.10 mol·Kg -1 盐酸混合溶液中 A 2- 的浓度约为( )。
A.
5.6×10 -16 mol·Kg -1
B.
1.6.0×10 -18 mol·Kg -1
C.
1.0×10 -20 mol·Kg -1
D.
2.1×10 -19 mol·Kg -1
【简答题】How can waste from living things be reused?
【单选题】What can an exhaust system do if it is efficient?
A.
It can prevent the waste gas from escaping.
B.
It can let the waste gas and compound escape quickly out of it.
C.
It can prevent the engine from producing waste gas.
D.
It can store as much waste gas as possible.
【单选题】已知 25 °C 时 , 某二元弱酸 H 2 A 的 K a1 θ = 1.0×10 -7 , K a2 θ = 1.0×10 -14 ,则 0.10mol ・ kg -1 H 2 A 溶液中 A 2– 的浓度约为( ) ; 在 0.10 mol·Kg -1 H 2 A 和 0.10 mol·Kg -1 盐酸混合溶液中 A 2- 的浓度约为 1.0×10 -20 mol·Kg -1 。
A.
1.0×10 -14 mol·Kg -1
B.
1.3×10 -14 mol·Kg -1
C.
2.1×10 -14 mol·Kg -1
D.
3.1×10 -14 mol·Kg -1
【判断题】效度只有程度上的差异,没有“全”和“无”。
A.
正确
B.
错误
【简答题】有关的技术分析著作常将缺口划分为??、??、持续性缺口和消耗性缺口四种形态。
【单选题】What can be inferred from the fourth paragraph?
A.
Farm areas accept waste from the city in modem society.
B.
There is cheap land to bury waste in modem society.
C.
It is difficult to find space to bury waste in modem society.
D.
Ways to deal with waste in modem society stay the same.
【判断题】Her beauty captured him instantly.
A.
正确
B.
错误
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