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阅读理解 Do you know there are two kinds of football games? One is American football, the other is soccer. In China many young men like playing soccer. It is very popular in China. But the Chinese don't call it soccer. They call it football. There are eleven players in a team. And the ball is round. Only the goal-keeper ( 守门员 ) can play the ball with hands. The other players must play the ball with feet. In America soccer is not very popular. I like playing American football more than playing soccer. There are also eleven players in a team. The ball is not round. All the players play the ball with hands and feet. American football is quite different from soccer. 根据短文内容完成句子 1. The Chinese call soccer . 2. There are players in a team of soccer and also in a team of American football. 3. In USA, people play football with hands and _____. 4. Only the can play football hands in England. 5. American football is from soccer.
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A.
. 6 7 8 9 10
B.
. 1 3 5 7 9
C.
. 1 2 3 4 5
D.
. 2 4 6 8 10
【单选题】Wallerstein's study showed that ______.
A.
divorce left the children with many problems
B.
all the problems showed up right after the divorce
C.
divorce could be avoided
D.
divorce made the children mature earlier
【单选题】有以下程序: #include int f( int x , int y) { return((y - x)*x) ; } main() { int a = 3 , b = 4 , c = 5 , d ; d = f(f(a , b) , f(a , c)) ; printf("%d\n" , d) ; } 程序运行后的输出结果是 ( ) 。
A.
7
B.
10
C.
8
D.
9
【单选题】有以下程序: #include int f(int x) ; main() { int n=1 , m ; m=f(f(f(n))) ; printf("%d\n" , m) ; } int f(int x) { return x*2 ; }
A.
运行后的输出结果是(  )。
B.
8
C.
2
D.
4
E.
1
【单选题】Many family law advisors offer legal advice for couples in divorce issues with a comparatively low fee.
A.
Y
B.
N
C.
NG
【简答题】提前订购期,也指生产周期
【单选题】The author holds that the divorce case of Beverley Charman has
A.
stirred up the question of what a woman is worth.
B.
demonstrated the priceless value of an exemplary woman.
C.
reflected the complexity of the question about a woman's value.
D.
proved lawyers may help couples to make the right decision.
【单选题】有以下程序 #include double f (double x); main() { double a=0; int i; for ( i=0; i<30; i+=10 ) a +=f( (double)i ); printf ("%3.0f\n", a); } double f (double x) { return x*x+1; } 程序运行后的输出结果是( ...
A.
500
B.
401
C.
503
D.
1404
【单选题】有以下程序 #include void fun( int a, int b, int c ) { a=b; b=c; c=a; } main() { int a=10 , b=20, c=30; fun( a, b, c ); printf("%d,%d,%d\n",c,b,a); } 程序运行后的输出结果是
A.
10,20,30
B.
30,20,10
C.
20,30,10
D.
0,0,0
【单选题】有以下程序 #include int fun( int a, intB) { return a+b; } main() { int x=6, y=7, z=8, r ; r = fun ( fun(x,y), z-- ); printf (" %d\n" , r ); } 程序运行后的输出结果是
A.
21
B.
15
C.
20
D.
31
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