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【单选题】
滞后-超前校正装置的是，随着频率的增大（）A.
先超前再滞后
B.
先滞后再超前
C.
不超前也不滞后
D.
同时超前滞后
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举一反三
【单选题】In any divorce case, both parties may NOT follow the binding decision if______.
A.
the arbitrator was biased
B.
the arbitrator asked them to pay for costs
C.
the arbitrator made a gross error of law
D.
the arbitrator exceeded his authority
【单选题】Wallerstein's study showed that ______.
A.
divorce left the children with many problems
B.
all the problems showed up right after the divorce
C.
divorce could be avoided
D.
divorce made the children mature earlier
【单选题】Many family law advisors offer legal advice for couples in divorce issues with a comparatively low fee.
A.
Y
B.
N
C.
NG
【简答题】提前订购期,也指生产周期
【单选题】The author holds that the divorce case of Beverley Charman has
A.
stirred up the question of what a woman is worth.
B.
demonstrated the priceless value of an exemplary woman.
C.
reflected the complexity of the question about a woman's value.
D.
proved lawyers may help couples to make the right decision.
【单选题】有以下程序 #include double f (double x); main() { double a=0; int i; for ( i=0; i<30; i+=10 ) a +=f( (double)i ); printf ("%3.0f\n", a); } double f (double x) { return x*x+1; } 程序运行后的输出结果是( ...
A.
500
B.
401
C.
503
D.
1404
【单选题】有以下程序 #include void fun( int a, int b, int c ) { a=b; b=c; c=a; } main() { int a=10 , b=20, c=30; fun( a, b, c ); printf("%d,%d,%d\n",c,b,a); } 程序运行后的输出结果是
A.
10,20,30
B.
30,20,10
C.
20,30,10
D.
0,0,0
【单选题】有以下程序 #include int fun( int a, intB) { return a+b; } main() { int x=6, y=7, z=8, r ; r = fun ( fun(x,y), z-- ); printf (" %d\n" , r ); } 程序运行后的输出结果是
A.
21
B.
15
C.
20
D.
31
【简答题】Another important factor is the 6 relaxation of divorce law in many states.
【简答题】In the case of negotiating divorce, a negotiator is asked to conform. to the principle of ______.
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