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● FTP协议是Internet常用的应用层协议，它通过 (59) 协议提供服务，它是基于client/Server结构通信的，作为服务器一方的进程，通过监听 (60) 端口得知有服务请求，在一次会话中，存在 (61) 个TCP连接。 (59) A．UDP B．TCP C．IP D．IPX (60) A．23 B．21 C．25 D．80 (61) A．0 B．1 C．2 D．3
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【简答题】Generally, the pH value of normal rain is 5-6. However, the pH value of acid rain is .
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【单选题】The hemoglobin content of their blood is only about _______ the normal value of 15 to 16 g/100 ml, because sickled cells are very fragile and rupture easily; this results in anemia. An even more serio...
A.
1/4
B.
1/2
C.
1/3
D.
1/5
查看完整题目与答案
【单选题】患者男,35岁。因车祸导致多根多处肋骨骨折,出现右侧胸壁浮动,极度呼吸困难。患者呼吸时,患处最可能出现
A.
吸气和吸气时均内陷
B.
吸气时外突,呼气时内陷
C.
吸气和呼气时均外突
D.
吸气和呼气时无明显变化
E.
吸气时内陷,呼气时外突
查看完整题目与答案
【单选题】The pancreatic glucokinase of a patient with MODY had a mutation replacing a leucine with a proline. The result was that the Km for glucose was decreased from a normal value of 6 mM to a value of 2.2 ...
A.
The patient ’ s enzyme requires a lower concentration of glucose to reach ½ Vmax.
B.
The patient ’ s enzyme is faster than the normal enzyme at concentrations of glucose <2.2 mM.
C.
The patient ’ s enzyme is faster than the normal enzyme at concentrations of glucose >2.2 mM.
D.
At near-saturating glucose concentration, the patient would need 90 to 100 times more enzyme than normal to achieve normal rates of glucose phosphorylation.
E.
As blood glucose levels increase after a meal from a fasting value of 5 to 10 mM, the rate of the patient ’ s enzyme will increase more than the rate of the normal enzyme.
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【单选题】患者男,35岁。因车祸导致多根多处肋骨骨折,出现右侧胸壁浮动,极度呼吸困难。患者呼吸时,患处最可能出现
A.
吸气和呼吸时均内陷
B.
吸气时外突,呼气时内陷
C.
吸气和呼气时均外突
D.
吸气和呼吸时无明显变化
E.
吸气时内陷,呼气时外突
查看完整题目与答案
【单选题】患者男,35岁。因车祸导致多根多处肋骨骨折,出现右侧胸壁浮动极度呼吸困难。此时给予该患者的首要处理措施是
A.
固定胸腔
B.
吸氧
C.
应用抗生素
D.
半卧位
E.
补充血容量
查看完整题目与答案
【简答题】Translate : Usually, a constancy of physiological variable requires a feedback mechanism that feeds the output information back to the control system so as to modifify the nature of control. Negative ...
查看完整题目与答案
【单选题】What is the normal value of the buffer pair-- HCO 3 - /H 2 CO 3 in the blood?
A.
、 2:1
B.
、 10:1
C.
、 20:1
D.
、 25:1
查看完整题目与答案
【简答题】Usually, a constancy of physiological variable requires a feedback mechanism that feeds the output information back to the control system so as to modify the nature of control. Negative feedback syste...
查看完整题目与答案
【单选题】What is the normal value of the Na + mole concentration in the blood?
A.
、 130 ～ 150mmol/L
B.
、 135 ～ 150mmol/L
C.
、 135 ～ 155mmol/L
D.
、 130 ～ 155mmol/L
查看完整题目与答案
相关题目：
【简答题】Generally, the pH value of normal rain is 5-6. However, the pH value of acid rain is .
查看完整题目与答案
【单选题】The hemoglobin content of their blood is only about _______ the normal value of 15 to 16 g/100 ml, because sickled cells are very fragile and rupture easily; this results in anemia. An even more serio...
A.
1/4
B.
1/2
C.
1/3
D.
1/5
查看完整题目与答案
【单选题】患者男,35岁。因车祸导致多根多处肋骨骨折,出现右侧胸壁浮动,极度呼吸困难。患者呼吸时,患处最可能出现
A.
吸气和吸气时均内陷
B.
吸气时外突,呼气时内陷
C.
吸气和呼气时均外突
D.
吸气和呼气时无明显变化
E.
吸气时内陷,呼气时外突
查看完整题目与答案
【单选题】The pancreatic glucokinase of a patient with MODY had a mutation replacing a leucine with a proline. The result was that the Km for glucose was decreased from a normal value of 6 mM to a value of 2.2 ...
A.
The patient ’ s enzyme requires a lower concentration of glucose to reach ½ Vmax.
B.
The patient ’ s enzyme is faster than the normal enzyme at concentrations of glucose <2.2 mM.
C.
The patient ’ s enzyme is faster than the normal enzyme at concentrations of glucose >2.2 mM.
D.
At near-saturating glucose concentration, the patient would need 90 to 100 times more enzyme than normal to achieve normal rates of glucose phosphorylation.
E.
As blood glucose levels increase after a meal from a fasting value of 5 to 10 mM, the rate of the patient ’ s enzyme will increase more than the rate of the normal enzyme.
查看完整题目与答案
【单选题】患者男,35岁。因车祸导致多根多处肋骨骨折,出现右侧胸壁浮动,极度呼吸困难。患者呼吸时,患处最可能出现
A.
吸气和呼吸时均内陷
B.
吸气时外突,呼气时内陷
C.
吸气和呼气时均外突
D.
吸气和呼吸时无明显变化
E.
吸气时内陷,呼气时外突
查看完整题目与答案
【单选题】患者男,35岁。因车祸导致多根多处肋骨骨折,出现右侧胸壁浮动极度呼吸困难。此时给予该患者的首要处理措施是
A.
固定胸腔
B.
吸氧
C.
应用抗生素
D.
半卧位
E.
补充血容量
查看完整题目与答案
【简答题】Translate : Usually, a constancy of physiological variable requires a feedback mechanism that feeds the output information back to the control system so as to modifify the nature of control. Negative ...
查看完整题目与答案
【单选题】What is the normal value of the buffer pair-- HCO 3 - /H 2 CO 3 in the blood?
A.
、 2:1
B.
、 10:1
C.
、 20:1
D.
、 25:1
查看完整题目与答案
【简答题】Usually, a constancy of physiological variable requires a feedback mechanism that feeds the output information back to the control system so as to modify the nature of control. Negative feedback syste...
查看完整题目与答案
【单选题】What is the normal value of the Na + mole concentration in the blood?
A.
、 130 ～ 150mmol/L
B.
、 135 ～ 150mmol/L
C.
、 135 ～ 155mmol/L
D.
、 130 ～ 155mmol/L
查看完整题目与答案
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