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Announcement Forest apartment June 5 RE: New Director We have been looking for our new director in the last 3 months. After an extensive search, we finally found the right person who will be succeeding the former director, Tony Adams. Nicole Sanders, the new director of the community life of Forest, brings twenty years of experience. Nicole Sanders was formerly the director of the Trinity Housing Complex and the student advisor of Bransford University where she received a degree in marketing. If you need her help, please drop by Apartment 15 before June 30, and she will move into Apartment 8. As requested, the auditorium for residents will be equipped with new air conditioning systems and ventilation systems. We will install light fixtures to improve lighting at Temple Lounge. In the back of Temple Lounge, an enclosed and designated play area will be prepared for young children. What is the purpose of the information?A.
To advertise an opening position
B.
To notify residents of building a new auditorium
C.
To provide information to the residents
D.
To raise some money for renovation
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【简答题】武术教学: 2 、 长拳: 3 、 集体表演: 4 、 “劲力”: 5 、武术基本功 :
【单选题】循环队列存储在数组A[0..m],则出队的操作为()
A.
*x=q->element[q->front]; q->front=(q->front+1);
B.
q->front=(q->front+1); *x=q->element[q->front];
C.
*x=q->element[q->front]; q->front=(q->front+1)%（m+1）;
D.
*x=q->element[q->front]; q->front=(q->front+1)%m;
【单选题】循环队列存储在数组A[0...n],则入队时的操作为
A.
rear=rear+1
B.
rear=(rear+1)mod(n-1)
C.
rear=(rear+1)mod n
D.
rear=(rear+1)mod(n+1)
【单选题】循环队列存储在数组A[m]中,则入队列操作中队列尾指针rear的变化为
A.
rear=rear+1
B.
rear=(rear+1)%(m-1)
C.
rear=(rear+1)%m.
D.
rear=(rear+1)%(m+1)
【单选题】循环队列存储在数组A[m]中,则进队列的操作为( )。
A.
rear=rear+1
B.
rear=(rear+1)%(m-1)
C.
rear=(rear+1)%m
D.
rear=(rear+1)%(m+1)
【单选题】循环队列存储在数组A[m]中,则入队时的操作为( )。
A.
rear=rear+1
B.
rear=(rear+1) mod (m-1)
C.
rear=(rear+1) mod m
D.
rear=(rear+1)mod(m+1)
【单选题】循环队列存储在数组A[0…m]中，则入队时的操作为( )。
A.
rear=rear+1
B.
rear=(rear+1)mod(m一1)
C.
rear=(rear+1)mod m
D.
rear=(rear+1)mod(m+1)
【单选题】循环队列存储在数组A[0..m]中,则入队时的操作为
A.
rear=rear+1
B.
rear=(rear+1) mod (m-1)
C.
rear=(rear+1) mod m
D.
rear=(rear+1)mod(m+1)
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