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【简答题】
确立语文课程目标的依据有:教育方针、_____、课程性质、_____、国内外经验等。
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参考答案:
举一反三
【单选题】定时器T100的定时范围为( )。
A.
0.1~3276.7s
B.
0.01~327.67s
C.
0.001~32.767s
D.
1~32767s
【单选题】下面的代码中,可以实现翻转数组操作的是()
A.
#include using namespace std; int main() { int a[10] = {1,2,3,4,5,6,7,8,9,10}; int begin = 0,end = 9; int tmp; while(begin < end) { tmp=a[begin]; a[begin]=a[end]; a[end]=tmp; begin++; end--; } for(int i=0;i < 10;i++) { cout << a[i] << ' ' ; } cout << endl; return 0; }
B.
#include using namespace std; int main() { int a[10] = {1,2,3,4,5,6,7,8,9,10}; int begin = 0,end = 9; int tmp; while(begin < end) { tmp=a[begin]; a[begin]=a[end]; a[end]=tmp; } for(int i=0;i < 10;i++) { cout << a[i] << ' ' ; } cout << endl; return 0; }
C.
#include using namespace std; int main() { int a[10] = {1,2,3,4,5,6,7,8,9,10}; int begin = 0,end = 9; while(begin < end) { a[begin]=a[end]; a[end]=a[begin]; } for(int i=0;i < 10;i++) { cout << a[i] << ' ' ; } cout << endl; return 0; }
D.
#include using namespace std; int main() { int a[10] = {1,2,3,4,5,6,7,8,9,10}; int begin = 0,end = 10; int tmp; while(begin < end) { tmp=a[begin]; a[begin]=a[end]; a[end]=tmp; begin++; end--; } for(int i=0;i < 10;i++) { cout << a[i] << ' ' ; } cout << endl; return 0; }
【单选题】A proven method for effective textbook reading is the SQ3R method developed by Francis Robinson. The first step is to survey (the S step) the chapter by reading the title, introduction, section headin...
A.
needs to be proven
B.
leaves much to he desired
C.
turns out to be practicable
D.
cannot be used by every reader
【简答题】______ is a method of rapidly moving the eyes over a text with the purpose of getting the main idea or a general overview of its content. 2. It can help you get the ______, the ______ of the reading m...
【单选题】定时器T100的定时范围为( )。
A.
0.1~3276.7s
B.
0.01~327.67s
C.
0.001~32.767s
D.
1~32767s
E.
【单选题】下列可以实现数组元素求和的代码段的是( )
A.
int[] scores = {90,80,70,89,100}; int sum=0; for(int i=1;i sum+=scores[i]; } System.out.println("数组元素和是:"+sum);
B.
int[] scores = {90,80,70,89,100}; int sum=0; for(int i=0;i<=score.length;i++){ sum+=score[i]; } System.out.println("数组元素和是:"+sum);
C.
int[] score = {90,80,70,89,100}; int sum=0; for(int i=1;i<=score.length;i++){ sum+=score[i]; } System.out.println("数组元素和是:"+sum);
D.
int[] scores = {90,80,70,89,100}; int sum=0; for(int score : scores){ sum+=score ; } System.out.println("数组元素和是:"+sum);
【简答题】A proven method for effective textbook reading is the SQ3R method developed by Francis Robinson. The first is to survey (the S step) the chapter by reading the title, introduction, section headings, s...
【判断题】100ms 积算定时器( T250 ~ T255 )共 6 点,是对 100ms 时钟脉冲进行累积计数的定时的时间范围为 0.1 ~ 3276.7s 。
A.
正确
B.
错误
【单选题】定时器T100的定时范围为( )。
A.
0.1~3276.7s
B.
0.01~327.67s
C.
0.001~32.767s
D.
1~32767s
【单选题】在MSR路由器上,ping命令的-t参数指定ICMPEchoReply报文的超时时间,取值范围为1~65535,单位为毫秒,它的默认值为()毫秒。
A.
200
B.
100
C.
2000
D.
1000
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