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【单选题】
i=i 1 +i 2 +i 3 =4 √2sinωtA+8√2sin(ωt+90°)A+4√2sin(ωt-90°)A,则总电流I的表示式为( )A.
I=4 √2∠45° A
B.
I=4 √2∠-45° A
C.
I=4∠45 °A
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